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Thermochemistry

Subject: Chemistry
Topic: 6
Cambridge Code: 0620 / 0971 / 5070


Energy in Reactions

Exothermic Reactions

Definition: Release energy (heat) to surroundings

  • Temperature increases
  • Combustion, neutralization
  • ΔH = negative
  • Products lower energy than reactants

ReactantsProducts+Heat\text{Reactants} → \text{Products} + \text{Heat}

Examples:

  • Burning fuel: CH₄ + 2O₂ → CO₂ + 2H₂O + heat
  • Neutralization: HCl + NaOH → NaCl + H₂O + heat

Endothermic Reactions

Definition: Absorb energy from surroundings

  • Temperature decreases
  • Photosynthesis, melting, evaporation
  • ΔH = positive
  • Products higher energy than reactants

Reactants+HeatProducts\text{Reactants} + \text{Heat} → \text{Products}

Examples:

  • Photosynthesis: 6CO₂ + 6H₂O + light → C₆H₁₂O₆ + 6O₂
  • Melting ice: Ice + heat → Water

Enthalpy Change (ΔH)

Enthalpy (H) - Total heat content

Enthalpy change (ΔH): ΔH=HproductsHreactantsΔH = H_{\text{products}} - H_{\text{reactants}}

Sign Convention

  • ΔH < 0: Exothermic (heat released)
  • ΔH > 0: Endothermic (heat absorbed)

Units

  • J/mol (joules per mole)
  • kJ/mol (kilojoules per mole)
  • Often written: ΔH = -393 kJ/mol

Calorimetry

Calorimetry - Measure heat change in reactions

Heat Equation

q=mcΔTq = mc\Delta T

where:

  • q = heat energy (joules)
  • m = mass (grams)
  • c = specific heat capacity (J/g°C)
  • ΔT = temperature change (°C)

Common Specific Heat Capacities

Substancec (J/g°C)
Water4.18
Aluminum0.897
Iron0.449
Copper0.385

Example Calculation

Problem: 100 g water heated from 20°C to 30°C (c = 4.18)

q=100×4.18×(3020)q = 100 \times 4.18 \times (30-20) q=100×4.18×10=4180 Jq = 100 \times 4.18 \times 10 = 4180 \text{ J}

Bomb Calorimeter

  • Insulated chamber
  • Combustion occurs in sealed container
  • Temperature rise measured
  • Accurate for combustion reactions

Simple Calorimeter

  • Beaker with thermometer
  • Less accurate (heat loss to surroundings)
  • Laboratory use

Hess's Law

Hess's Law - Enthalpy change independent of reaction pathway

ΔHoverall=ΔHequationsΔH_{\text{overall}} = \sum ΔH_{\text{equations}}

Application

Find ΔH of difficult reaction using known reactions

Example: Find ΔH for: C(s) + O₂(g) → CO₂(g)

Given:

  1. C(s) + ½O₂(g) → CO(g), ΔH₁ = -110.5 kJ
  2. CO(g) + ½O₂(g) → CO₂(g), ΔH₂ = -283.0 kJ

Solution:

  • Add equations 1 + 2:
  • C(s) + O₂(g) → CO₂(g), ΔH = -110.5 + (-283.0) = -393.5 kJ

Reversing Equations

If reverse equation: ΔH changes sign

Example:

  • Forward: H₂ + ½O₂ → H₂O, ΔH = -286 kJ
  • Reverse: H₂O → H₂ + ½O₂, ΔH = +286 kJ

Scaling Equations

If multiply by factor n: ΔH also multiplies by n

Example:

  • Given: N₂ + 3H₂ → 2NH₃, ΔH = -92 kJ
  • Multiply by 2: 2N₂ + 6H₂ → 4NH₃, ΔH = -184 kJ

Standard Enthalpy Change of Formation (ΔHf°)

ΔHf° - Enthalpy change when 1 mole of compound forms from elements in standard state

Standard state: Most stable form at 25°C, 1 atm

Values

ΔHf° = 0 for elements in standard state

  • O₂(g) has ΔHf° = 0
  • C(s) has ΔHf° = 0

ΔHf° for compounds: Tabulated values available

Calculating ΔH°reaction

ΔH°reaction=(ΔH°f products)(ΔH°f reactants)ΔH°_{\text{reaction}} = \sum (ΔH°_f \text{ products}) - \sum (ΔH°_f \text{ reactants})

Example: CH₄ + 2O₂ → CO₂ + 2H₂O

Using standard enthalpies of formation


Breaking and Forming Bonds

Bond Energy

Bond energy - Energy needed to break bond or released when formed

Energy Calculation

ΔH=(bond energies broken)(bond energies formed)ΔH = \sum \text{(bond energies broken)} - \sum \text{(bond energies formed)}

Example: H₂ + Cl₂ → 2HCl

  • Bonds broken: H-H (436 kJ) + Cl-Cl (244 kJ) = 680 kJ
  • Bonds formed: 2 × H-Cl (432 kJ) = 864 kJ
  • ΔH = 680 - 864 = -184 kJ (exothermic)

Fuel Value

Fuel value - Energy released per mass of fuel

Fuel value=Energy released (kJ)Mass of fuel (g)\text{Fuel value} = \frac{\text{Energy released (kJ)}}{\text{Mass of fuel (g)}}

Examples

FuelValue (kJ/g)
Hydrogen141
Methane55.5
Ethanol29.6
Coal30

Higher value = Better fuel


Key Points

  1. Exothermic: ΔH < 0 (heat released)
  2. Endothermic: ΔH > 0 (heat absorbed)
  3. Heat equation: q = mcΔT
  4. Hess's Law: ΔH independent of pathway
  5. ΔHf° for elements = 0
  6. Bond energy: Breaking requires energy, forming releases
  7. Fuel value: Energy per unit mass

Practice Questions

  1. Classify reactions as exothermic/endothermic
  2. Calculate heat using q = mcΔT
  3. Apply Hess's Law to calculate ΔH
  4. Use ΔHf° values to find ΔH°reaction
  5. Calculate from bond energies
  6. Compare fuel values

Revision Tips

  • Know exothermic/endothermic clearly
  • Practice calorimetry calculations
  • Understand Hess's Law
  • Learn ΔHf° concept
  • Know bond energy calculations
  • Know equation manipulation rules
  • Practice multiple approaches