Subject: Mathematics
Topic: 4
Cambridge Code: 0580
Differentiation
Differentiation - Finding rate of change (derivative)
Concept
Derivative f′(x) - Rate of change of f(x)
- Instantaneous rate of change
- Slope of tangent line
- Velocity (if x is time)
Definition
f′(x)=limh→0hf(x+h)−f(x)
Differentiation Rules
Power rule:
dxd(xn)=nxn−1
Example: dxd(x3)=3x2
Constant rule:
dxd(c)=0
Constant multiple:
dxd(cf(x))=c⋅f′(x)
Sum rule:
dxd(f(x)+g(x))=f′(x)+g′(x)
Product rule:
dxd(f(x)g(x))=f′(x)g(x)+f(x)g′(x)
Quotient rule:
dxd(g(x)f(x))=[g(x)]2f′(x)g(x)−f(x)g′(x)
Chain rule:
dxd(f(g(x)))=f′(g(x))⋅g′(x)
Derivatives of Special Functions
dxd(sinx)=cosx
dxd(cosx)=−sinx
dxd(ex)=ex
dxd(lnx)=x1
Applications of Differentiation
Finding Stationary Points
Stationary points - Where f′(x)=0
Types:
- Maximum: f′′(x)<0
- Minimum: f′′(x)>0
- Inflection: f′′(x)=0 (changes concavity)
Second Derivative Test
f′′(x)=dxd(f′(x))
- f′′(x)>0: Concave up (minimum)
- f′′(x)<0: Concave down (maximum)
- f′′(x)=0: Possible inflection point
Optimization
To find maximum/minimum value:
- Find f′(x)
- Set f′(x)=0, solve for x
- Find corresponding y-value
- Verify with second derivative or context
When multiple variables change together:
dtdV=drdV⋅dtdr
Motion Problems
Position: s(t) (distance at time t)
Velocity: v(t)=dtds (rate of position change)
Acceleration: a(t)=dtdv=dt2d2s (rate of velocity change)
Integration
Integration - Reverse of differentiation; finding area
Basic Integration
Indefinite integral:
∫xndx=n+1xn+1+C,n=−1
Constant of integration: C (arbitrary constant)
Integration Rules
Sum rule:
∫(f(x)+g(x))dx=∫f(x)dx+∫g(x)dx
Constant multiple:
∫cf(x)dx=c∫f(x)dx
Integrals of Special Functions
∫exdx=ex+C
∫x1dx=ln∣x∣+C
∫sinxdx=−cosx+C
∫cosxdx=sinx+C
Definite Integration
Definite integral - Area between curve and x-axis
Fundamental Theorem of Calculus
∫abf(x)dx=[F(x)]ab=F(b)−F(a)
Where F is antiderivative of f
Area Under Curves
Between curve and x-axis:
Area=∫abf(x)dx
Between two curves:
Area=∫ab∣f(x)−g(x)∣dx
Numerical Integration
Trapezoid rule:
∫abf(x)dx≈2h[f(x0)+2f(x1)+2f(x2)+...+2f(xn−1)+f(xn)]
Where h=nb−a
Differential Equations
Differential equation - Equation involving derivatives
Separable Equations
dxdy=f(x)g(y)
Solution:
∫g(y)dy=∫f(x)dx
Example
dxdy=2x,y(0)=1
y=x2+1
Key Points
- Derivative is rate of change
- Power rule most common differentiation rule
- Chain rule for composite functions
- Stationary points where f'(x) = 0
- Second derivative determines max/min
- Integration is reverse of differentiation
- Definite integral gives area
- Trapezoid rule approximates area
- Related rates connect changing quantities
- Differential equations model real processes
Practice Questions
- Differentiate using various rules
- Find stationary points
- Determine max/min values
- Solve optimization problems
- Integrate various functions
- Evaluate definite integrals
- Find areas under curves
- Find areas between curves
- Solve motion problems
- Solve differential equations
Revision Tips
- Master differentiation rules thoroughly
- Practice chain rule extensively
- Understand what derivative represents
- Know special function derivatives
- Practice optimization problems
- Understand integration as area
- Learn definite integral evaluation
- Connect to real-world applications
- Verify answers by working backward